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</span><table border="0" align="center" width="95%" cellpadding="3" cellspacing="1"><tr><td>Quote (Kreator @ Sep. 22 2002,06:21)</td></tr><tr><td id="QUOTE">So does that mean that the turbo on the first KA would actually spool up at lower RPM? Or do you just mean engine spool up (meaning KA#1 would get to that rpm faster)? But how does the torque affect the velocity of the exiting gas? Wouldn't it depend much more on the engine rpms??</td></tr></table><span id='postcolor'>
I believe the higher torque of the engine pushs more air per engine revolution at the lower rpm's making the turbo spool up faster. The second ka, with not as much torque, isn't pushing as much air at the lower rpms, so its not getting as much velocity for quick spool up.
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