Anyone good at math?

[StryfeS13]

Sup guys. I'm having a bit of trouble answering these two problems in my college "Refreshment Math" class.

I know that there is a way I can set up my calculator so I can use TAN to answer them, but I can't figure out how to configure it.

Mods, if this breaks rules in any way please close and delete my thread. I just need a little help on this. I just figured this would be the only appropriate section to post this in.

In the first problem it is supposed to say, "Find "a" if 0 is 60."

[pacotaco345]

Set your calculator to degrees... sin=opp/adj, cos=adj/hyp, tan=opp/adj. I'd just answer it for you but I don't know what you want me to find in the first one.

[cardoza]

That first question makes no sense, if theta was a 60 degree angle then that would make it a 30-60-90 right triangle, meaning that C would have to be double the length of B, or 46. According to the laws of geometry, A would be 39.84, but that would be assuming that C was following those rules. As for the rules of sine and cosine, I haven't done that for 7 years so I'm pretty rusty.

[cardoza]

Here's a diagram of how a 30-60-90 triangle should go.

[StryfeS13]

@pacotaco, I don't know how to set it in degrees...I know it'd be something like 90 / 58 = TAN, but Idk, i don't get it.

Here is a better photo of the first question.

[90hatchie]

i read this quickly and was lioke "WTF WHOS GOOD AT METH"??
then i read into this and my head hurt......alot
math baddddddddd

[StryfeS13]

^Hahaha. I hate math, I just can't understand it.

[TheWolf]

All interior triangle angles equal 180 degrees. Every time without fail. It's a staple of 8th grade geometry.

So in your problem. you have a 60 degree angle. and a 90 degree angle. Take 180-60-90= answer. Now finding the side lengths

"Set your calculator to degrees... sin=opp/adj, cos=adj/hyp, tan=opp/adj." that will work if they allow you to use scientific calculators

if not then you'll need to use pytag's theorum. A^2 + B^2 = C^2
Your answer is then simple algebra with square roots.

[smoked240]

Hahaha. Triangles. First identify which is Hyp,Adl,opp. Since 60 is in the bottom right corner That tells me that B= adj C=hyp A=opp.
Sin=O/H
Cos=A/H
Tan=O/A

Your trying to find the opp length and you know the adj and hyp sides.
Which calculator do you have?

I believe it's tan(60)*23=A
If I remember right Py's theorum will give him a different answer then he is looking for, But I am not 100% positive.

[theicecreamdan]

Originally Posted by TheWolf

All interior triangle angles equal 180 degrees. Every time without fail. It's a staple of 8th grade geometry.

If your triangle is on a plane, then yes.

Using pythagorean I get
sqrt(53^2-23^2)=47.75

Using 30-60-90
I get
23*sqrt(3) = 39.84
OR
(58/2)*sqrt(3)= 50.22

or sin(theta)=a/c
sin(60)*58=a if your calculator is stuck on radians then your angle is (pi)/3
a=50.22

or tan(theta)=a/b
tan(60)*23=a
a=39.84

etc.


Basically, for plane geometry, that triangle is a lie.

For the building
cos(75)=20/h
tan(75)=0/20

75degrees -> radians
75 degrees = 1.30899694 radians (google 75 degrees to radians)

Or you could figure it out (pi)/6 is 30 degrees, so (pi)/12 is 15 degrees
75 is 90-15
90 is (pi)/2
(pi)/2-(pi)/12
6(pi)/12-(pi)/12
5*(pi)/12 is the radian equivalent of 75 degrees

(5 * pi) / 12 = 1.30899694

[smoked240]

Everything you need, He knows. /\.

[KOUKIboy]

WTF!!! Math??!! hell no!! lol Math gives me headaches, do what I do copy the smart guy next to you JK lol

[exitspeed]

Pretty sure the answer is 7.

[97nismo]

its.............

sin (theta)= opposite / hypotenuse

sin(60)= a/58

a= 50.22

[axiomatik]

There is no valid answer to the first question. Those dimensions do not result in a right-triangle.

Because it is shown as a right-triangle, Pythagorean Theorem applies: a^2 + b^2 = c^2

or:
a = sqrt(c^2 - b^2)
a = sqrt(58^2 - 23^2)
a = sqrt(3364 - 529)
a = sqrt(2835)
a = 53.24

However, tan(theta) = Opposite/Adjacent

tan(60) = a/b
a = b*tan(60)
a = 23*tan(60)
a = 23*1.73
a = 39.84

Notice that the 2 answers are not the same. Out of curiosity, I drew the triangle in Autocad real fast. Those dimensions result in a 97 deg angle, not a 90 degree angle shown in the bottom left corner.

[jahmias]

pythagorean theorem, a^2 + b^2= c^2
A squared + B squared = C squared where A and B are the adjacent to the right angle and C is the hypotenuse. if you know two of the three you can use algebra to deduce the third number. if i member correctly.