2008 Beijing Summer Olympics Thread

[jskateborders]

Originally Posted by AkademikONE

It's official. Olympic gymnastics is rigged.
Nastia Liukin was ROBBED of the gold medal.
Absolutely ROBBED. Kexin and Liuikin had the same
start value, and final score, yet Kexin had absolutely
more noticeable errors then Liukin, including a not-so-perfect
dismount landing, where Nastia nailed hers. The damn tie-breaker
gave the gold to Kexin, and even though the tie-breaker awarded
the right person, it never should have been a tie in the first place.

Im sorry, but your post confuses me.... do you think that kexin should have won or liukin?

[ALTRNTV]

Originally Posted by jskateborders

Im sorry, but your post confuses me.... do you think that kexin should have won or liukin?

What I mean that, with the circumstances, the tie-breaker
awarded the right person and did the job it was suppose to,
due to the scores they got, BUT, that tie NEVER should have
happened in the first place. I hope that's clearer to understand.

Originally Posted by score

A complete score is now made up of two parts, A and B. The first, the A score, or the start value, is an assigned degree of difficulty.I n this instance, both He and Liukin had the same start value, 7.7.

The second part of a score, the B score, is an execution score. Six judges vote. The high and the low are tossed per the rules.
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That leaves four scores. Those four are averaged. That average becomes the B score. Add the A and B together and you get a complete score.

In this instance, both He and Liukin got 16.725.

Thus: onto tiebreakers.

The first tiebreak is the B score. Here both got the same B score, 9.025.

The next tiebreak: the judges drop the next highest deduction. That obviously leaves three judges' scores instead of four -- or to be precise, the marks those three judges gave for deductions.

Here, the average of those three judges' deductions for He: .933. For Liukin: .966.

Liukin had a greater deduction. Thus she was second.

Another way of getting to that math: Take the B scores of the three judges from that second tie-break, add them together and divide by three.

The math for He: 9.1, 9.1, 9.0. That equals 27.2. Divide that by three, and that equals 9.066, the sixes stretching out to infinity.

For Liukin: 9.1, 9.0, 9.0. That equals 27.1. Divide that by three and it's 9.0333, the threes going out forever.

Thus she was second.