</span><table border="0" align="center" width="95%" cellpadding="3" cellspacing="1"><tr><td>Quote (William @ Mar. 07 2002,12:45)</td></tr><tr><td id="QUOTE">I have to disagree slightly. If turbo A is more efficient at a certain cfm and pressure ratio than turrbo B, it will make more power. Why? Because efficiency of a turbo is measured by how well it can move the air without heating it more than the laws of thermodynamics say it should. So, for the same application, if turbo A is %78 efficient at 18psi, and turbo B is only %60 efficient, turbo A will be packing a lot more oxygen per molecule of air. Oxygen is power.</td></tr></table><span id='postcolor'>
I would've let this go if you didn't disagree.. <img src="http://www.zilvia.net/f/iB_html/non-cgi/emoticons/mad.gif" border="0" valign="absmiddle" alt=':angry:'> Efficiency of a turbo can only refer to energy of outgoin air comparing to energy of incoming air. that's how you measure eff., using energy, not the amount of oxygen molecules. Energy loses thru heat lost, how well the turbines transfer energy to air (gaining pressure); and even through sound. Atmosphere can not change it's % of oxygen just by compressing and decompressing air so you're wrong there too. Also, if what you say is true, which is not, 78% eff. has exactly 1.3 time more oxygen molecules than 60%eff in same amount of air. that does not translate into the huge HP gain from larger turbos, like I said, not a main reason for it. (even if it's true)
stay in school is paying off... lol..
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K. Lu
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